помогите пж хелп (3х + 4)2 – (3х – 1)(3х + 1) = 41

Question

помогите пж хелп (3х + 4)2 – (3х – 1)(3х + 1) = 41

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Alice 1 год 2021-09-26T00:29:02+00:00 1 Answers 0 views 0

Answers ( )

  1. (3х+4)2-(3х-1)(3х+1)=41

    6х+8-(9х²-1)=41

    6х+8-9х²+1=41

    6х+9-9х²=41

    6х+9-9х²-41=0

    6х-32-9х²=0

    9х²-6х+32=0

    D=b²-4ac= (-6)²-4×9×32=-1116

    D<0→нет действительных корней

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