(х+1)²-(х-3)(х+3)=7 помагите ппжжжжж 100 балл берем

Question

(х+1)²-(х-3)(х+3)=7 помагите ппжжжжж
100 балл берем

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Natalia 1 год 2021-09-23T12:28:29+00:00 1 Answers 0 views 0

Answers ( )

  1. Lydia
    0
    2021-09-23T12:30:11+00:00
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    (х+1)²-(х-3)(х+3)=7

    х²+2х+1-(х²-9)=7

    х²+2х+1-х²+9=7

    2х+10=7

    2х=7-10

    2х=-3

    х=–3/2 – 1 1/2

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